Fix Set-Location : A positional parameter cannot be found that accepts argument | InvalidArgument

Fix Set-Location : A positional parameter cannot be found that accepts argument | InvalidArgument


Fix Set-Location : A positional parameter cannot be found that accepts argument | InvalidArgument

In this video, I will explain how to fix the error message in PowerShell - A positional parameter cannot be found that accepts argument

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Content

0 -> in this video I'll be showing you how to
2.7 -> resolve a situation whereby from
5.88 -> Powershell you try to change directory
8.94 -> to a folder and you receive the
10.5 -> following error message which says in
12.54 -> positional parameter cannot be found to
15.66 -> accept argument and for example the
19.68 -> folder name so here at this moment you
22.439 -> can see I'm actually at my C drive when
24.539 -> I enter the following directory that's
26.34 -> the day I Arrow that's the shortcut for
28.32 -> directory so I received the following
30.48 -> you can see these are all the folders on
32.399 -> my T drive but you can see I have a
35.7 -> folder called temp folder so I'm
38.219 -> actually trying to change to that term
40.379 -> folder
42.12 -> and you can see I'm receiving an error
44.46 -> message so Powershell does not allow you
47.219 -> to actually enter a folder um that has
50.579 -> two names without a quotation mark so
53.219 -> I'm going to enter the following CD the
55.62 -> quotation term folder and then you
59.039 -> actually close it and hit enter and
61.32 -> right now you can see I'm actually I can
63.78 -> actually move now to that folder so the
66.24 -> CD means change directory thank you very
69.96 -> much for your time and please don't
71.28 -> forget to like this video and hit the
73.38 -> Subscribe button thank you very much and
75.9 -> goodbye

Source: https://www.youtube.com/watch?v=29n1hIfcbSI